Well yesterday on my day off I decided to follow the procedures documented on this forum to remove my rear wheel on my '97 standard Valkyrie. Everything was going fine until I tried to loosen the rear axle nut on the left side. The 27MM one. I was using a long breaker bar and I thought I broke the nut loose but soon realized that the axle was actually turning all the way through to the right side of axle housing. I then saw that the center of the axle nut on the right side uses a hex socket. Well according to the procedures in this forum and others it indicates that a 8mm hex socket would fit into the right side of the axle nut. Well I found out that 8mm is slightly too large and 7mm is too small. So I have two questions:
1) What size is the hex socket on the right side of the axle? 7.5mm maybe?
2) any suggestions on how to loosen the 27mm nut on the left side of the axle?
This is ticking me off.

I just want to remove the wheel to get a new tire mounted.
Anyone's help would be greatly appreciated.
Thanks
Gerry