So, I would like to add what is known as a "Fake Alarm LED light".
I would like to add a small LED light that ONLY comes on when the key is in the OFF position.
Ok so now with reading the info from the first picture, Can I assume if I pick up a 5 pin relay as my primary relay for my AUX fuse panel that is ONLY energized when the key is in the on position. That I can pick up one of those pre built +12volt blinking LED and run a HOT +12volt to one side of the LED and then run a wire back to the relay and attach it to the 87a pin in the center of the relay? When the key is in the off position and the relay does NOT have power triggering it to make contact with pin 87 and that 87a becomes a grounded circuit thus making my circuit to the LED complete and allowing it to operate and blink?
One like this is what I am talking about a prebuilt +12volt flashing LED.
http://www.frys.com/product/1334006?site=sr:SEARCH:MAIN_RSLT_PGDoes this make any sense to anyone?
Thanks in advance.
... sorry but I get confused when I read your note..... so I will start from fresh...
Wire in a control wire from the ignition to 85 and connect terminal 86 to ground
Supply adequate power to terminal 30 from the battery positive , now... 87a will have power in key off position, 87 will have power in key on position
.... if you have already done other modifications to your stock electrical system and have incorporated 5 pin relays into it to control such things as an auxiliary power panel or headlights then you may have a relay that is "keyed" and is not using 87a terminal and so you could now utilise it to power up an LED when the key is in teh off position. If you have a multimeter or continuity probe style tester you should be able to check 87a by grounding the tester black and then with either the tester red or probe touch teh 87a terminal and if it has power with the key switch in the off position then you could utilise that to power your LED indicator.